Can someone plz make a histogram for the numbers 60,60,65,71,72,75,80,88,92,95,100,152

HELP PLEASE

vitfil [10]

It’s 1 because of -8x^4-x^2+2

3 0

4 years ago

1. In 25 minutes Li can run 10 laps around the track. Determine the number of laps she can run per minute.

antiseptic1488 [7]

Answer:

For the first example, the constant of proportionality should be .4 of a mile, meaning that Li can run .4 mile per minute. The equation should be .4x = y. For the second example, it is easy to find the constant of proportionality because it is given, which is 2. The equation to represent this would be 2x = y.

Step-by-step explanation:

The reason why the constant of proportionality is .4 is because I used the ratio from before and compared it to the one needed. I simply turned the ratios into fractions and I cross multiplied before turning it into a equation to solve to find .4 as the constant of proportionality. The equation should be .4x = y because x = the amount of minutes Li ran, and y = the total amount of miles she ran. The reason why the constant of proportionality is 2 in the second problem is because Jennifer is paying 2 per pound, which is the unit rate. If we are looking at the cost per pound, it would mean that 2 is the constant of proportionality. The reason why the equation to represent this would be 2x = y is because x = the amount of pounds, and y = the total amount of money, which represents the situation.

8 0

3 years ago

Read 2 more answers

You sketch a right triangle that has a hypotenuse of 13 centimeters, and one leg that is 8 centimeters. How many centimeters is

olasank [31]

Hello from MrBillDoesMath!

Answer:

sqrt(105)

(which is approximately 10.25 centimeters )

Discussion:

Call the unknown leg"a". From the Pythagorean theorem

8^2 + a^2 = 13^2 => subtract 8^2 = 64 from both sides

a^2 = 13^2 - 64 => as 13^2 = 169

a^2 = 169 - 64 = 105 => take the square root of both sides

a = sqrt(105) which is approximately 10.25 centimeters

Thank you,

MrB

8 0

3 years ago

Read 2 more answers

Find an equation for the tangent to the curve at P and the horizontal tangent to the curve at Q. y = 5 + cot x - 2 csc x 0 1 2 3

oksian1 [2.3K]

Answer with explanation:

The given function in x and y is,

y= 5 +cot x-2 Cosec x

To find the equation of tangent, we will differentiate the function with respect to x

$y'= -\csc^2 x+2 \csc x\times \cot x$

Slope of tangent at (π/2,3)

$y'_{(\frac{\pi}{2},3)}= -\csc^2\frac{\pi}{2} +2 \csc \frac{\pi}{2}\times \cot \frac{\pi}{2}\\\\=-1+2\times 1 \times 0\\\\= -1$

Equation of tangent passing through (π/2,3) can be obtained by

$\rightarrow \frac{y-y_{1}}{x-x_{1}}=m(\text{Slope})\\\\ \rightarrow \frac{y-3}{x-\frac{\pi}{2}}=-1\\\\\rightarrow 3-y=x-\frac{\pi}{2}\\\\\rightarrow x+y-3-\frac{\pi}{2}=0$