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vampirchik [111]
3 years ago
7

Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

Mathematics
1 answer:
ad-work [718]3 years ago
7 0
<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

(3^56^8)(3^96^{10})

Given Conner's work is:

(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}

We have to check if this work is correct

Yes, Conner work is correct

From given,

(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}

Use the following law of exponent

a^m \times a^n = a^{m+n}

Therefore,

3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}

<em><u>Given Jana's work is:</u></em>

(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

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ANTONII [103]

Mark Achin's economic order quantity in units is <u>D. 120​ units</u>.

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The economic order quantity (EOQ) is the optimal order quantity that minimizes the total costs (ordering, receiving, and holding inventory).

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3 0
2 years ago
Please help me :(<br>NO LINKS PLEASE<br>​
liubo4ka [24]

Answer:

Option A

Step-by-step explanation:

<u>Given equation is:</u>

x^2+1=2x-3

Setting it up as a quadratic equation.

x^2+1-2x+3=0\\\\x^2-2x+4=0

Comparing it with quadratic equation ax^2+bx+c=0, we get:

a = 1 , b = -2 , c = 4

<u>Putting the values in quadratic equation:</u>

\displaystyle x = \frac{-b +-\sqrt{b^2-4ac} }{2a} \\\\x = \frac{-(-2)+-\sqrt{(-2)^2-4(1)(4)}  }{2(1)}

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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Someone help pleasee
Semenov [28]

Answer:

a horizontal translation 3 units to the right because-3 has been added to the exponent

3 0
3 years ago
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