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vampirchik [111]
3 years ago
7

Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

Mathematics
1 answer:
ad-work [718]3 years ago
7 0
<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

(3^56^8)(3^96^{10})

Given Conner's work is:

(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}

We have to check if this work is correct

Yes, Conner work is correct

From given,

(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}

Use the following law of exponent

a^m \times a^n = a^{m+n}

Therefore,

3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}

<em><u>Given Jana's work is:</u></em>

(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

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