To solve this problem shown in the image attached, you must apply the following proccedure:
1. You have the following quadratic equation:
2x^2-2x-12=0
2. When you factor the quadratic equation shown above, you obtain:
2(x^2-x-6)=0
2(x-3)(x+2)=0
3. Then, you obtain:
(2x-6)(x+2)=0
Therefore, as you can see, the correct answer is the Option C.
In figure A, you would want to go up 2 and across right 6 to get to A'. In figure 2 you can go up 1 then across right 2.
We presume you want to find values of x that make this true.
Subtract the right side and factor:
Once you have factors whose product is zero, you can find the values of x that make those factors zero. A product can only be zero if one or more contributing factors is zero.
To solve 2x-5=0, you can add 5 then divide by 2:
... 2x -5 = 0
... 2x = 5
... x = 5/2
Answer: correct buttt u need to put 82y in there
Step-by-step explanation: if you dont put 82y in there the awnser is wrong good luck
The answer is 30 because 10×3=30