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frozen [14]
3 years ago
8

Angel is shopping in a department store for sneakers.

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

65 dollars and 2 cent

Step-by-step explanation:

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4(0.2x-5)=12 what is x
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Can you help answer this question
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Use the substitution method to solve the system of equations. y = -8x 4x - y = 3 O AG-2 O B. (6-1 oc c. (6.-4 D. G-4​
Triss [41]
<h2>x = 1/4</h2><h2>y = -2</h2><h2>______________</h2>

<h2>Known : </h2>

y = -8x

4x - y = 3

<h2>Asked: </h2>

Use the substitution method to solve the system of equations ?

<h2>Answered:</h2>

<h3>Substitution y</h3>

4x - y = 3

4x - (-8x) = 3

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x = 1/4

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Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

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3 years ago
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