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3 years ago

Angel is shopping in a department store for sneakers.

Mathematics

1 answer:

BartSMP [9]3 years ago

6 0

Answer:

65 dollars and 2 cent

Step-by-step explanation:

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4(0.2x-5)=12 what is x

Genrish500 [490]

Answer: skksskk

Step-by-step explanation:

kssmns

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3 years ago

Can you help answer this question

Darina [25.2K]

1:b
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3 years ago

Use the substitution method to solve the system of equations. y = -8x 4x - y = 3 O AG-2 O B. (6-1 oc c. (6.-4 D. G-4

Triss [41]

<h2>Known : </h2>

y = -8x

4x - y = 3

<h2>Asked: </h2>

Use the substitution method to solve the system of equations ?

<h2>Answered:</h2>

<h3>Substitution y</h3>

4x - y = 3

4x - (-8x) = 3

4x + 8x = 3

12x = 3

x = 3/12

x = 1/4

<h3>Substitution x</h3>

4x - y = 3

4(1/4) - y = 3

4/4 - y = 3

1 - y = 3

-y = 3 - 1

-y = 2

y = -2

6 0

3 years ago

Read 2 more answers

3 divide by 9.2 in a decimal

lys-0071 [83]

The answer is 0.3260869565. you can round that

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3 years ago

Two vertical poles of length 10 and 12 feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the

Marat540 [252]

Answer:

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft$

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

$x^{2} +10^{2}=L_{1} ^{2} \\x^{2} + 100 = L_{1} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\ \sqrt{x^{2}+100}= L_{1}$

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

$(17-x)^{2}+12^{2}=L_{2} ^{2} \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}} \\\sqrt{x^{2}-34x+433}=L_{2}$

Amount of cable used, L = L1 + L2

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}$

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3 years ago