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12345 [234]
3 years ago
5

En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que

el otro, pero su diámetro es la mitad del diámetro del otro. El tarro más alto vale $4.500 y el más bajo $8.000, ¿ cuál es la mejor compra ? help
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

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Drupady [299]

Answer:

  • $5000 at 10%, $10000 at 12% and 10000 at 16%

Step-by-step explanation:

  • <em>One part of $ 25,000 is invested at 10% interest, another part at 12%, and the rest at 16%. The total annual income from the three investments is $ 3,200. Also, the income from the investment at 16% is equal to the income from the other two investments combined. How much was invested at each interest rate?</em>

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Let the parts be x, y and z

<u>As per given we get below system of equations:</u>

  • x + y + z = 25000
  • 0.1x + 0.12y + 0.16z = 3200
  • 0.1x + 0.2y = 0.16z

<u>Substitute 0.1x + 0.2y in the second equation:</u>

  • 0.16z + 0.16z = 3200
  • 0.32z = 3200
  • z = 3200/0.32
  • z = 10000

<u>Now we have:</u>

  • x + y + 10000 = 25000 ⇒ x + y = 15000

and

  • 0.1x + 0.12y + 0.16*10000 = 3200 ⇒ 0.1x + 0.12y = 1600

<u>Multiply the second equation and then subtract the first one:</u>

  • 10(0.1x + 0.12y) = 10(1600) ⇒ x + 1.2y = 16000
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  • 0.2y = 1000
  • y = 10000

Then

  • x = 15000 - 10000 = 5000

<u>So the parts are:</u>

  • $5000 at 10%, $10000 at 12% and 10000 at 16%
4 0
2 years ago
Can I get some help? Thanks!
expeople1 [14]

Answer:

The answer would be b.

Step-by-step explanation:

We can easily use process of elimination here. a would not be correct because it's saying that as you move forward, you increase when it's the total opposite. You are decreasing as you move forward.

C and D would not be correct because they both are talking about 0 temperature, and there is no data for that temperature.

So B is the correct answer.

If you liked my answer, please consider giving me a Brainliest! Thank you!

7 0
3 years ago
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