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Marrrta [24]
3 years ago
15

If angle KLJ~angle VWU. Find the x value

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

17

Step-by-step explanation:

Since angle KLJ~angle VWU are similar :

KL / WV = KJ/ UV

(25 / 20) = (4x - 23 / 2x + 2)

Cross multiply :

25(2x + 2) = 20(4x - 23)

50x + 50 = 80x - 460

50x - 80x = - 460 - 50

-30x = -510

x = 510 / 30

x = 17

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If it were two hours later,it would be half as long until midnight as it would be if it were an hour later. what time is it now.
mafiozo [28]

Answer:

its 10 am I think

Step-by-step explanation:

it says 2 hours until midnight. 12 - 2 = 10

7 0
3 years ago
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You see a news headline which claims that tuition at CSU San Jose is going to increase by 7% next year. If tuition for in-state
wolverine [178]

The tuition would be $6143.94 next year

<h3>How to detemrine the tuition amount?</h3>

The given parameters are:

  • Current amount = $5,742
  • Rate of increment, r = 7%

The tuition next year is then calculated as:

Tuition = Current * (1 + Rate)

This gives

Tuition = $5,742 * (1 + 7%)

Evaluate

Tuition = $6143.94

Hence, the tuition would be $6143.94 next year

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brainly.com/question/25545513

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6 0
2 years ago
Write an equation in standard form of the line that passes through the given points (-2,6) (-8,-5)
Lunna [17]
Find the slope
m= -5-6 / -8-(-2)
m= -11/-6
m=11/6

Use slope and point to create equation
y-6= 11/6(x-(-2))
y-6=11/6x+22/6
y=11/6x+58/6
y=11/6x+29/3

Change to standard form
Standard form: ax + by = c
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8 0
3 years ago
Read 2 more answers
A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weig
jenyasd209 [6]

Answer:

z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625    

The p value for this case would be given by:

p_v =P(z  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

Step-by-step explanation:

Information provided

\bar X=19.87 represent the sample mean

\sigma=0.4 represent the population deviation

n=25 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:  

Null hypothesis:\mu \geq 20  

Alternative hypothesis:\mu < 20  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing the info given we got:

z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625    

The p value for this case would be given by:

p_v =P(z  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

7 0
3 years ago
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