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3 years ago

Rotate shape A 180° with centre of rotation (3,-1).

Mathematics

1 answer:

Elis [28]3 years ago

8 0

Answer:

Step-by-step explanation:

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Find the perimeter and area of the figure.

iogann1982 [59]

Answer:

perimeter of the figure =32 units

area of the figure=56 units²

8 0

3 years ago

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

3 years ago

5 2x=2x 6 how do you solve this problem

Maslowich

If it is 5+2x=2x+6 than the answer is no solution

7 0

3 years ago

Find the domain of h(x)=x-3/x^3-36x

Dovator [93]

There is some ambiguity here which could be removed by using parentheses. I'm going to assume that you actually meant:

x-3

h(x) = ---------------

(x^3-36x)

To determine the domain of this function, factor the denominator:

x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)

The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.

Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."

Symbolically, the domain is (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).

3 0

4 years ago

Rewrite the following sentence as an equation.

SVEN [57.7K]

Answer:

3(2+x)=0

Step-by-step explanation:

<u>Here are some vocab words:</u>

Product: Multiplication

Sum: Addition

"A number": x

3(2+x)=0

6 0

3 years ago