Question

For questions 4 – 7, answer the questions about secant-secant angles.

Answer 1

Answer:

4). m∠DAE = 23°

5). m(∠BAE) = 29.5°

Step-by-step explanation:

4). "Angle formed by the intersection of two tangents and secants outside the circle is half of the difference of intercepted arcs"

m∠DAE = $\frac{1}{2}(62-16)$

             = $\frac{46}{2}$

             = 23°

5). Following the same rule as in question 4,

m(∠BAE) = $\frac{1}{2} [m(\text{arc BE})-m(\text{arc CD})]$

                    = $\frac{1}{2}(88-29)$

                    = $\frac{59}{2}$

                    = 29.5°