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UNO [17]
3 years ago
7

Find the exact value of cot( sin-'(-1)).O A. UndefinedO B. OO C. -1O D. 1​

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0
B. 0. type it into your inspire calculator and this is the answer

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What percentage of $15 is 75 cent​
Aleks04 [339]

Answer: What percentage is 15 out of 75?

20

Percentage Calculator: 15 is what percent of 75? = 20.

5 0
2 years ago
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How do you simplify the radical √144 ?
SVETLANKA909090 [29]

Answer:

its 12

Step-by-step explanation:

you find whats closest for example, 10 squared is 100.

100 is close to 144

and 11x11= 121

so you would do 12

12x12 is 144

8 0
3 years ago
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Hannah buys 2/3 pound of roast beef. She uses 1/4 pound to make sandwiches for lunch. How much roast beef does she have left?
Vanyuwa [196]
First we need to make both fractions equal to each other, and that means having to have the denominators the same.

What both 3 and 12 easily go into is 12.

So we need to make both fractions have a denominator of 12, so we multiply.

2/3 * 4/4 = 8 / 12

1/4 * 3/3 = 3 / 12

Now, we know that she has 8 / 12 pounds, and she uses 3 / 12 of it, so now we subtract to find how much she has left.

8 - 3 = 5

Out of the 12 pounds of roast beef, she now has 5 / 12 left.
7 0
2 years ago
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Grace's car left four skid marks on the road surface during a highway accident. Two of the skid marks were each 52 feet and two
Mashcka [7]

Answer:

The skid distance to be used is 54 feet.

Step-by-step explanation:

Given:

Four skid marks on the highway.

52,52,56,56  in feet.

We have to find the skid distance.

The skid distance that will be used to further calculate the skid speed is actually the mean skid distance.

Mean skid distance (m) :

⇒ (m)=\frac{Sum\ of \ the\ skid\ marks }{Number\ of\ skid\ marks}

⇒ (m) =\frac{52+52+56+56}{4}

⇒ (m) =\frac{216}{4}

⇒ (m)=54  feet.

So the skid distance to be used is 54 feet.

7 0
2 years ago
A negative number minus a positive number is always negative true or false?
MariettaO [177]

Answer:

False

Step-by-step explanation:

7 0
3 years ago
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