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Grace [21]
3 years ago
14

Please help Asap

Mathematics
2 answers:
daser333 [38]3 years ago
5 0
The answer is 8. :).
taurus [48]3 years ago
3 0

Answer: either 15.75  or 8

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Does anyone know this lol i just need a short explanation
maks197457 [2]

Answer: pretty sure it’s because the left and bottom sides add up to equal the top side

Step-by-step explanation:

4 0
3 years ago
A town determined that the function f(x) - 820(0.977* models the number of speeding tickets issued in the town x years after 200
Rom4ik [11]

Answer:D The number of tickets is increasing by 97% each year

Step-by-step explanation:

The rate of change is (0.97). You change that decimal into a percent To get your percentage rate / increase rate...I think

3 0
3 years ago
If you shift the linear parent function, (X) = x down 6 units, what is the
jeka94

Answer:

<h2>C. g(x) = x - 6</h2>

Step-by-step explanation:

For a parent function y = f(x) and n > 0:

f(x) + n : move the graph n units up

f(x) - n : move the graph n units down

f(x + n) : move the graph n units to the left

f(x - n) : move the graph n units to the right

===================================================

We have

f(x) = x

Transformation: 6 units down

f(x) - 6 = x - 6

3 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
The length of a rectangle is 5 yd longer than its width.
romanna [79]

Answer:

w = 13yd, l = 18yd

Step-by-step explanation:

let x be width, so x+5 = length

Perimeter is sum of all 4 sides, and since opposite sides equal in rectangle,

P = 2(l+w)

  = 2(x+5 +x)

  = 4x + 10

Since perimeter is give as 62yd, equation is

4x + 10 = 62

4x = 52

x = 13

8 0
2 years ago
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