Question

Elisa has 10 gold colored coins and 6 silver colored coins. She selects 2 coins with replacement. What is the probability she selects 2 silver colored coins.

Answer 1

Answer:

Step-by-step explanation:

p=number of silver coins/total number of coins

p=3/8 of 3/8=9/64

Answer 2

Answer: $\frac{9}{64}$

Step-by-step explanation:

n(gold colored coins) = 10

n(silver colored coins) = 6

Total number of coins = 16

since there is replacement , the probability she selects 2 silver colored coins will be :

$\frac{6}{16}$ x $\frac{6}{16}$

= $\frac{3}{8}$ x $\frac{3}{8}$

= $\frac{9}{64}$

Therefore : the probability she selects 2 silver colored coins is $\frac{9}{64}$