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muminat
2 years ago
15

5x-4y=19 x+2y=8 solve the simaltaneous equation

Mathematics
1 answer:
STatiana [176]2 years ago
8 0

Answer:

( 5, 3/2 )

x = 5

y = 3/2

Step-by-step explanation:

5x - 4y = 19

x + 2y = 8

-------------------

2(x + 2y = 8) = 2x + 4y = 16

----------------------

5x - 4y = 19

2x + 4y = 16

7x = 35

÷7    ÷7

x = 5

-----------------------

x + 2y = 8

5 + 2y = 8

-5          -5

2y = 3

÷2   ÷2

y = ( 3/2 )

I hope this helps!

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Thomas invested $1498.00 at 6% simple interest per annum calculate How long it will be before his investment earns $449.40
valentinak56 [21]

Answer:

t = 6 years

Step-by-step explanation:

Use the simple interest formula:  i = prt, where p is the principal, r is the interest rate as a decimal fraction, and is the elapsed time, in years.

Here we want to know how long it will take for the interest alone to reach $449.40.  We first solve i = prt for t, obtaining t = i/(pr).

Here, the length of time is t = ($449.40) / (0.06*$1498.00).  This works out to

t = 5.9947, or approximately 6 years.

t = 6 years

8 0
3 years ago
Please help on this one (fast please)
Luba_88 [7]
The correct answer is d
7 0
3 years ago
Please help i don't understand
alexira [117]

Answer:

A

Step-by-step explanation:

The diagonals of a parallelogram bisect each other. Hence, the two shorter sides created on diagonal RT ("6x-7" and "x+28" ) are equal.

<em>We can set them equal and solve for x:</em>

<em>6x-7=x+28\\6x-x=28+7\\5x=35\\x=\frac{35}{5}\\x=7</em>

<em />

<em>So the side length of 6x -7 is:</em>

<em>6(7)-7 = 35</em>

<em>and the side length of x + 28 is:</em>

<em>7 + 28 = 35</em>

<em />

<em>THus, the diagonal RT = 35 + 35 = 70 units</em>

<em />

<em>Answer choice A is right.</em>

3 0
2 years ago
3х – 8y = — 16<br> =<br> M<br> So yeah I kinda need help
marishachu [46]

Answer:

3x-8y-16  = 0

Step-by-step explanation:

8 0
3 years ago
How do you do these questions?
Tanzania [10]

Answer:

μ ≈ 2.33

σ ≈ 1.25

Step-by-step explanation:

Each person has equal probability of ⅓.

\left[\begin{array}{cc}X&P(X)\\1&\frac{1}{3}\\2&\frac{1}{3}\\4&\frac{1}{3}\end{array}\right]

The mean is the expected value:

μ = E(X) = ∑ X P(X)

μ = (1) (⅓) + (2) (⅓) + (4) (⅓)

μ = ⁷/₃

The standard deviation is:

σ² = ∑ (X−μ)² P(X)

σ² = (1 − ⁷/₃)² (⅓) + (2 − ⁷/₃)² (⅓) + (4 − ⁷/₃)² (⅓)

σ² = ¹⁴/₉

σ ≈ 1.25

3 0
3 years ago
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