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Bumek [7]
3 years ago
10

George is given two circles, circle O and circle X 1 as shown. If he wants to prove that the two circles are similar, what would

be the correct first step in his proof? Given: The radius of circle Oisrand the radius of circle Xis Prove: Circle similar to circle X.

Mathematics
1 answer:
salantis [7]3 years ago
6 0

Answer:

Step-by-step explanation:

Given: The radius of circle O is r, and the radius of circle X is r'.

To prove: Circle O is similar to circle X.

Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.

A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.

The scale factor x to increase X:

⇒

A translation followed by a dilation with scale factor  will map one circle to the other, thus proving the given both circles similar.

Therefore, circle O is similar to circle X.

Step-by-step explanation:

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How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
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Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

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Answer:

A

Step-by-step explanation: i am in math 8

lol

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