George is given two circles, circle O and circle X 1 as shown. If he wants to prove that the two circles are similar, what would
be the correct first step in his proof? Given: The radius of circle Oisrand the radius of circle Xis Prove: Circle similar to circle X.
1 answer:
Answer:
Step-by-step explanation:
Given: The radius of circle O is r, and the radius of circle X is r'.
To prove: Circle O is similar to circle X.
Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.
A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.
The scale factor x to increase X:
⇒
A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.
Therefore, circle O is similar to circle X.
Step-by-step explanation:
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Answer:
Solution given:
principal [P]=P
time [T]=4 years
Rate [R]=13%
compound amount=18900
Simple interest=P-18900
we have
simple interest=
P-18900=
100P-1890000=52P
48P=1890000
P=1890000/48
P=39375
the sum that amounts =Rs 39375
9514 1404 393
Answer:
y -4 = -2(x -(-11))
Step-by-step explanation:
The point slope formula is ...
y -k = m(x -h) . . . . . line with slope m through point (h, k)
__
So, the boxes in order from left to right are k, m, h.
The problem statement tells you the point is (-11, 4), so h = -11, k = 4. It also tells you the slope is -2, so m = -2.
Putting these numbers in the required order, we have k = 4, m = -2, h = -11 and the equation of the line is ...