Question

Find the area of parallelogram ABCD given m∠A = 30° and the following measures. AD = in.; AB = 8 in. A=

Answer 1

Answer:

16√3 in.²'

Step-by-step explanation:

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Answer 2

Answer: Given that a parallelogram ABCD has sides AB= 6 ft and AX = 3√3

Angle A =30

To find the area of the parallelogram

We have area of parallelogram = base x height

Here base can be taken as side AB = 6 ft

Height = perpendicular distance of AB from vertex X

= AX sin A

= 3√3sin30

=1.5√3

Hence area =6(1.5√3)=9√3ft^2

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