2 years ago

What are the answers for

Mathematics

1 answer:

Elden [556K]2 years ago

6 0

Answer:

7. 589.0

8. 122.0

9. 0.6

10. 3.5

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According to the rational root theorem, which is a factor of the polynomial f(x)=3x^3-5x^2-12x+20?

MakcuM [25]

Answer:

(x-2), (x+2), (3x-5)

Step-by-step explanation:

Factors of 3: ±1, ±3

Factors of 20: ±1, ±2, ±4, ±5, ±10, ±20

Possible factors of the polynomial: ±1, ±2, ±3, ±4, ±5, ±10, ±20, .... (there's a lot more but you probably do not need to list them all)

Pick a number to divide the polynomial by (I picked 2)

(3x³-5x²-12x+20)÷(x-2) = 3x²+x-10

So (x-2) is a factor of f(x) = 3x³-5x²-12x+20

Factor 3x²+x-10 = (3x-5)(x-2) these are the other factors of f(x) = 3x³-5x²-12x+20

4 0

3 years ago

Is the point (5,-1) a solution of y=2x-11

Nataly [62]

if the given point satisfies this equation then it would be its solution

(-1)=2(5)-11

-1=10-1

-1=-1

lHS=RHS

Hence (/,-1) is the solution of y=2x-11

3 0

3 years ago

HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-

Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

$f(x) =2x^3-9x^2+13x-6$

If x+1 is a factor , then f(-1) must evaluate to zero.

$f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6$

$f( - 1) =2( - 1)-9( 1)+13( - 1)-6$

$f( - 1) = - 2-9 - 13-6$

$f( - 1) = -11 - 19$

$f( - 1) = - 30$

Since f(-1) is not equal to zero, x+1 is not a factor of

$f(x) =2x^3-9x^2+13x-6$

6 0

3 years ago

PLEASE MATH HELP WILL GIVE BRAINLIEST

hram777 [196]

The answer is 32.72 degree.
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7 0

2 years ago

Help plsss, i need it asap!!!!! thankss

Elis [28]

With what ??? I don’t see nothing

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3 years ago