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3 years ago

10

Help me, worth 30 points

1 answer:

lutik1710 [3]3 years ago

6 0

Answer:

AC=10 BC=8

Step-by-step explanation:

Use Soh Cah Toa.

sin=opposite/hypotenuse

Cosine=adjacent/hypotenuse

Tangent=opposite/adjacent

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Two rectangles are shown below. Rectangle P has a perimeter of 20 inches. Rectangle Q has a perimeter of 30 inches. What are the

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The complete question in the attached figure

we know that
perimeter of a rectangle=2*[base+height]

rectangle P
perimeter=20 in
perimeter=2*[j+4+h]
20=2j+2h+8------> 2j+2h=12----> j+h=6-----> j=6-h------> equation 1

rectangle Q
perimeter=30 in
perimeter=2*[j+1+3h]
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substitute equation 1 in equation 2
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the answer is
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4 years ago

IRINA_888 [86]

X= 49 because the square root of 49 IS 7. :D
Good luck! :)

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3 years ago

find the surface areas of the larger cone and the smaller cone in terms of pi. compare the surface areas using a percent. (the m

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ANSWER :

Surface area of larger cone : 24π units^2

Surface area of smaller cone : 6π units^2

The surface area of the smaller cone is 25% of that of the larger cone.

EXPLANATION :

From the given problem,

AB = 3 is the radius of the larger cone and the slanted height is BC = 5

DE = 1.5 is the radius of the smaller cone and the slanted height is EC = 2.5

Recall the surface area of the cone :

$A=\pi r^2+\pi rL$

where r = radius and L = slanted height.

For the larger cone, r = 3 and L = 5

$\begin{gathered} A=\pi(3)^2+\pi(3)(5) \\ A=24\pi \end{gathered}$

For the smaller cone, r = 1.5 and L = 2.5

$\begin{gathered} A=\pi(1.5)^2+\pi(1.5)(2.5) \\ A=6\pi \end{gathered}$

Comparing the surface areas :

The area of the smaller cone compared to the larger cone is :

$\begin{gathered} \frac{smaller}{larger}\times100=\frac{6\pi}{24\pi}\times100 \\ \\ =25\% \end{gathered}$

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