Two rectangles are shown below. Rectangle P has a perimeter of 20 inches. Rectangle Q has a perimeter of 30 inches. What are the
values of j and h?
1 answer:
The complete question in the attached figure
we know that
perimeter of a rectangle=2*[base+height]
rectangle P
perimeter=20 in
perimeter=2*[j+4+h]
20=2j+2h+8------> 2j+2h=12----> j+h=6-----> j=6-h------> equation 1
rectangle Q
perimeter=30 in
perimeter=2*[j+1+3h]
30=2j+6h+2----> 2j+6h=28----> j+3h=14-------> equation 2
substitute equation 1 in equation 2
(6-h)+3h=14-----> 2h=8-----> h=4
j=6-h-----> j=6-4----> j=2
the answer is
j=2
h=4
we know that
perimeter of a rectangle=2*[base+height]
rectangle P
perimeter=20 in
perimeter=2*[j+4+h]
20=2j+2h+8------> 2j+2h=12----> j+h=6-----> j=6-h------> equation 1
rectangle Q
perimeter=30 in
perimeter=2*[j+1+3h]
30=2j+6h+2----> 2j+6h=28----> j+3h=14-------> equation 2
substitute equation 1 in equation 2
(6-h)+3h=14-----> 2h=8-----> h=4
j=6-h-----> j=6-4----> j=2
the answer is
j=2
h=4
You might be interested in
Answer:
Step-by-step explanation:
Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:
<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>
- <u />
- Directrices ->
- Foci ->
where
Since we are given our directrices of and foci of
, then we can set up the directrices equation to solve for
:
Now we can determine to complete our equation for the hyperbola:
Therefore, our equation for our hyperbola is
