Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
Answer:
Step-by-step explanation:
The numbers are 59 and 61
Answer:
The length of the pother piece of the wood is 25 cm.
Step-by-step explanation:
Let the length of a piece of wood is x such that the ratio of two pieces is 2:5. Two pieces are 2x and 5 x
Length of the first piece is 10 cm. It means, 2x = 10 i.e. x = 5
We have considered that the length of other piece is 5x. It means 5×5 = 25 cm.
Hence, the length of the pother piece of the wood is 25 cm
