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trapecia [35]
3 years ago
12

Find the distance between the given points . find the midpoint of the segment with the given endpoints. round to the nearest ten

th, if necessary
Mathematics
1 answer:
iris [78.8K]3 years ago
5 0
Whete are the given points, is thee a picture

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What is 5.68 x 10^4 in standard form
scZoUnD [109]

Answer:

Since the exponent of the scientific notation is positive  4, move the decimal point  4  places to the right.  

56800

Step-by-step explanation:

5.68(104)


=5.68*104


=5.68*(10*10*10*10)


=56800

7 0
3 years ago
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Write the equivalent fractions for 4/9 and 10/11 using the least common denominator
Tcecarenko [31]

Answer:

4/9 = 44/99

10/11 = 90/99

Step-by-step explanation:

44/99=90/99

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2 years ago
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Simplify 5(x - 6).<br><br> -x<br> 5x - 6<br> 5x - 30
Tamiku [17]
Hello! For this problem, we have to use the distributive property. So we do 5 * x and 5 * 6. When we do that, we get 5x - 30. The answer is C: 5x - 30.
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3 years ago
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Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.
KatRina [158]
AB = AU + UB = 20x + 108 + 273 = 20x + 381

\cfrac{AU}{AB} =\cfrac{UV}{BC}    \\  \\  \cfrac{20x+108}{20x+381} =\cfrac{444}{703}   \\  \\ 703(20x+108)=444(20x+381)\\\\14060x+75924=8880x+169164 \\  \\ 14060x-8880x = 169164 - 75924 \\  \\ 5180x = 93240 \\  \\ x=93240/5180 \\  \\ x=18
5 0
3 years ago
The travel time on a section of a Long Island Expressway (LIE) is normally distributed with a mean of 80 seconds and a standard
user100 [1]

Answer:

The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 80 seconds and a standard deviation of 6 seconds.

This means that \mu = 80, \sigma = 6

What travel time separates the top 2.5% of the travel times from the rest?

This is the 100 - 2.5 = 97.5th percentile, which is X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 80}{6}

X - 80 = 6*1.96

X = 91.76

The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.

3 0
2 years ago
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