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Burka [1]
3 years ago
12

Upon studying low bids for shipping contracts, a microcomputer manufacturing company finds that intrastate contracts have low bi

ds that are uniformly distributed between 22 and 29, in units of thousands of dollars. (a) Find the probability that the low bid on the next intrastate shipping contract is below $25,000. (Round your answer to four decimal places.)
Mathematics
1 answer:
Elena-2011 [213]3 years ago
8 0

Answer:

0.4286 = 42.86% probability that the low bid on the next intrastate shipping contract is below $25,000.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value lower than x is given by:

P(X < x) = \frac{x - a}{b - a}

Uniformly distributed between 22 and 29, in units of thousands of dollars.

This means that a = 22, b = 29.

(a) Find the probability that the low bid on the next intrastate shipping contract is below $25,000.

This is P(X < 25). So

P(X < 25) = \frac{25 - 22}{29 - 22} = 0.4286

0.4286 = 42.86% probability that the low bid on the next intrastate shipping contract is below $25,000.

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The new cylinder can has radius of 5cm and a height of 9cm how many square centimeters of aluminum will it take to make this new
m_a_m_a [10]

Answer: 282.85\ cm^2

Step-by-step explanation:

Given

Radius of cylinder r=5\ cm

The height of the cylinder is h=9\ cm

The surface area of a cylinder is 2\pi rh

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3 years ago
Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg
Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) <u>Optimal solution</u>: 40.000 units of R and 10.000 of PC = $17.000

c) <u>Slack variables</u>: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) <u>Binding Constaints</u>:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is  

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.  

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b. The particle is at rest whenever v(t)=0; this happens for

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