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The answer is: <u>2(k2−4k)(2c+5)</u>
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Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
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The tangents are equal length, so
.. 8x = x^2
We presume their length is not zero, so we can divide by x to get
.. 8 = 2x
.. 4 = x
Then the length of each tangent is 8*4 = 32 units.
Fifth root of x is x^1/5 as an exponential expression. . This to the 7th power is
x ^(1/5 * 7) which is x^(7/5). Bringing this to the third power is x^ (21/5) which is your answer.
Answer: 
Step-by-step explanation:
Use the pythagorean theorem 
plug in and solve



if you need to solve for the sides
3x = 3(4.7434) = 14.2302