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3 years ago

PLEASE HELP SEMESTER IS ALMOST OVER AND NEED MY GRADES UP!!!!!!!!

Mathematics

2 answers:

mojhsa [17]3 years ago

7 0

I believe that the answer is D

Arlecino [84]3 years ago

4 0

Answer:The Answer is D

Step-by-step explanation:

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Passes through (-6,-1) and is parallel to y=-2/3x+1

Troyanec [42]

Answer: y = -2/3x - 5

explanation: parallel slopes are the same, so the new equation would have a slope of -2/3. now, we have to find the y-intercept. to do this, plug in the x and y values for our new equation. we know that the standard form is y=mx+b, where b is the y-intercept.
-1 = -2/3(-6) + b
multiply
-1 = 4 + b
subtract 4 on both sides
-5 = b
so our new equation is
y = -2/3x - 5
you can check by plugging in the x-value (-6)
y= -2/3(-6) - 5
to get
y= -1
which makes this correct

7 0

3 years ago

pedro ran 2 more than 3/4 the number of miles that cierra ran. write an equation that represents the relationship between the nu

PIT_PIT [208]

2 more than = +2
3/4 the number of miles that Cierra ran = (3/4)c

p = (3/4)c + 2

7 0

3 years ago

Use the table to answer the following question.

AURORKA [14]

The answer is option A

5 0

3 years ago

Slove by dividing to the smallest unit and check your work .What is 28÷2086

Anuta_ua [19.1K]

74.5

you have to switch the numbers for it to be a proper division problem

Hope this helps!

6 0

4 years ago

Read 2 more answers

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

4 0

4 years ago