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cestrela7 [59]
2 years ago
9

7 to 2 = __to 6 help plz​

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
8 0

Answer:

19 would be the naswer

Step-by-step explanation:

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For k:<br><br>(j + k)/3 = 5​
Sphinxa [80]

Answer:

k=-j=15

Step-by-step explanation:

See attachment for step by step :)

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3 years ago
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What are the solutions to the quadratic equation 98-x2=0
kifflom [539]

98-x^2=0\qquad\text{add}\ x^2\ \text{to both sides}\\\\98=x^2\to x^2=98\\\\x=\pm\sqrt{98}\\\\x=\pm\sqrt{49\cdot2}\\\\x=\pm\sqrt{49}\cdot\sqrt2\\\\\boxed{x=-7\sqrt2\ \vee\ x=7\sqrt2}

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3 years ago
I need help first will be the brainiest!
Schach [20]

step 1

magsagot ka nang magsagot ng mga question yun lang basta maganda yung sagot mo

6 0
3 years ago
Please help due ASAP <br> Please show workings!!
Kazeer [188]

Answer:

FC = 27, QC = 18

Step-by-step explanation:

The centroid Q is \frac{1}{3} the way along CF , therefore, QF is half as long as CQ

Given FQ = 9, then

QC = 2 × 9 = 18

FC = FQ + QC = 9 + 18 = 27

8 0
3 years ago
Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

3 0
3 years ago
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