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2 years ago

9

7 to 2 = __to 6 help plz

1 answer:

Alex_Xolod [135]2 years ago

8 0

Answer:

19 would be the naswer

Step-by-step explanation:

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For k:<br><br>(j + k)/3 = 5

Sphinxa [80]

Answer:

k=-j=15

Step-by-step explanation:

See attachment for step by step :)

4 0

3 years ago

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What are the solutions to the quadratic equation 98-x2=0

kifflom [539]

$98-x^2=0\qquad\text{add}\ x^2\ \text{to both sides}\\\\98=x^2\to x^2=98\\\\x=\pm\sqrt{98}\\\\x=\pm\sqrt{49\cdot2}\\\\x=\pm\sqrt{49}\cdot\sqrt2\\\\\boxed{x=-7\sqrt2\ \vee\ x=7\sqrt2}$

8 0

3 years ago

I need help first will be the brainiest!

Schach [20]

step 1

magsagot ka nang magsagot ng mga question yun lang basta maganda yung sagot mo

6 0

3 years ago

Please help due ASAP <br> Please show workings!!

Kazeer [188]

Answer:

FC = 27, QC = 18

Step-by-step explanation:

The centroid Q is $\frac{1}{3}$ the way along CF , therefore, QF is half as long as CQ

Given FQ = 9, then

QC = 2 × 9 = 18

FC = FQ + QC = 9 + 18 = 27

8 0

3 years ago

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

3 0

3 years ago