Hope it helps with your work
Answer:
Option 4
Step-by-step explanation:
Term = n/(4^n)
(n+1)th term = (n+1)/[4^(n+1)]
Ratio: (n+1)/[4^(n+1)] ÷ n/(4^n)
= (n+1)/[4^(n+1)] × (4^n)/n
= [(n+1)/n] × (1/4)
For large n, (n+1)/n approaches 1
[(n+1)/n] × (1/4) approaches 1/4 which is less than 1
Since the ratio is less than 1, series converges
Answer:
<u> 105</u> students could prefer kiwi if there are 357 total students.
Step-by-step explanation:
Given:
The ratio of students who prefer pineapple to students who prefer kiwi is 12 to 5.
Now, to find number of students prefer kiwi if there are 357 total students.
Let the students prefer pineapple be 
And the students prefer kiwi be 
Total students = 357.
So, we set an equation to get the number of students who prefer kiwi.
According to question:
<em>Dividing both sides by 17 we get:</em>
<em>Thus, students prefer kiwi are:</em>
Therefore, 105 students could prefer kiwi if there are 357 total students.
1] Given that the value of x has been modeled by f(x)=12500(0.87)^x, then:
the rate of change between years 1 and 5 will be:
rate of change is given by:
[f(b)-f(a)]/(b-a)
thus:
f(1)=12500(0.87)^1=10875
f(5)=12500(0.87)^5=6230.3
rate of change will be:
(6230.3-10875)/(5-1)
=-1161.2
rate of change in years 11 to 15 will be:
f(11)=12500(0.87)^11=2701.6
f(15)=12500(0.87)^15=1,547.74
thus the rate of change will be:
(1547.74-2701.6)/(15-11)
=-288
dividing the two rates of change we get:
-288/-1161.2
-=1/4
comparing the two rate of change we conclude that:
The average rate of change between years 11 and 15 is about 1/4 the rate between years 1 and 5.
The answer is D]
2] Given that the population of beavers decreases exponentially at the rate of 7.5% per year, the monthly rate will be:
monthly rate=(n/12)
where n is the number of months
=7.5/12
=0.625
This is approximately equal to 0.65%. The correct answer is A. 0.65%
Answer:
12
Step-by-step explanation:
