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2 years ago

Given that point j is the incenter of triangle nop, find jk if jm = x-2 and jl = 3x - 8

Mathematics

1 answer:

mafiozo [28]2 years ago

5 0

Its 3. I hope this helps

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Y= (x-9) (x+3)

juin [17]

Answer:

y = x² − 6x − 27

Step-by-step explanation:

To distribute, you can use something called FOIL. It stands for First, Outer, Inner, Last.

First, multiply the First term in each factor.

x · x = x²

Now multiply the Outer terms in each factor.

x · 3 = 3x

Next multiply the Inner terms in each factor.

-9 · x = -9x

Finally, multiply the Last terms in each factor.

-9 · 3 = -27

Add them all up:

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x² − 6x − 27

4 0

2 years ago

Which expression is equivalent to (8^2)^-4

xz_007 [3.2K]

Answer:

C: $\frac{1}{8*8*8*8*8*8*8*8}$

Step-by-step explanation:

$a^{-n} = \frac{1}{a^n}$

Since a = $8^2$ :

$(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}$

Since n = 4 :

$(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}$

6 0

2 years ago

NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS ONLY PLZ WILL REPORT FAKE ANSWERS

Contact [7]

Answer:

Step-by-step explanation:

There is a common ratio between consecutive terms

r = 24 ÷ 16 = 36 ÷ 24 = 54 ÷ 36 = 1.5 = $\frac{3}{2}$

This indicates the sequence is geometric with nth term ( explicit formula )

f(n) = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 16 and r = $\frac{3}{2}$ , then

f(n) = 16 $(\frac{3}{2}) ^{n-1}$ → C

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1 year ago