Answer:
x-y=4
and
x+y=32 is <u>your</u><u> </u><u>equation</u>
<u>d</u><u>i</u><u>f</u><u>f</u><u>e</u><u>r</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>=</u><u>x-y</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>4</u>
<u>s</u><u>u</u><u>m</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>=</u><u>x</u><u>+</u><u>y</u><u> </u><u>i</u><u>s</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u><u> </u><u>t</u><u>o</u><u> </u><u>3</u><u>2</u>
<u>x</u><u>-</u><u>y</u><u>=</u><u>4</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>1</u><u>)</u>
<u>x</u><u>+</u><u>y</u><u>=</u><u>3</u><u>2</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>2</u><u>)</u>
<u>a</u><u>d</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>2</u>
<u>x</u><u>-</u><u>y</u><u> </u><u>+</u><u>x</u><u>+</u><u>y</u><u>=</u><u>4</u><u>+</u><u>3</u><u>2</u>
<u>2</u><u>x</u><u>=</u><u>3</u><u>6</u>
<u>x</u><u>=</u><u>3</u><u>6</u><u>/</u><u>2</u><u>=</u><u>1</u><u>6</u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>
<u>s</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>1</u>
<u>1</u><u>6</u><u>-</u><u>y</u><u>=</u><u>4</u>
<u>1</u><u>6</u><u>-</u><u>4</u><u>=</u><u>y</u>
<u>y</u><u>=</u><u>1</u><u>2</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>
Answer: The three different equations will be
Step-by-step explanation:
We have to write three equation that have x = 5 as a solution:
1) First equation will be
2) Second equation will be
3) Third equation will be
Hence, the three different equations will be
Answer:
4
Step-by-step explanation:
0.25 to the -1 power is 4
Using the principle of proportional relationship, the amount of weight lost by hedgedog in 120 days is 3.6 oz
<u>Proportional</u><u> </u><u>relationships</u><u> </u><u>are</u><u> </u><u>defined</u><u> </u><u>thus</u><u> </u><u>:</u>
- y = kx
- <em>k</em><em> </em><em>=</em><em> </em><em>constant</em><em> </em><em>of proportionality</em><em> </em>
Taking a piar of points :
-0.24 = 8k
<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>8</em>
(-0.24/8) = k
k = - 0.03
Hence, hedgedog loses weight at a rate of - 0.03 oz per day.
<u>The</u><u> </u><u>amount</u><u> </u><u>of</u><u> </u><u>weight</u><u> </u><u>lost</u><u> </u><u>in</u><u> </u><u>120</u><u> </u><u>days</u><u> </u><u>:</u>
The proportional relationship = y = - 0.03x
<em>Substitute</em><em> </em><em>x</em><em> </em><em>into</em><em> </em><em>the</em><em> </em><em>equation</em><em> </em>
y = -0.03(120)
y = - 3.6 oz
Therefore, the amount of weight lost in 120 days is 3.6 oz.
Learn more : brainly.com/question/25308816