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3 years ago

Find the circumference of a circle with a diameter of 45.

Mathematics

2 answers:

sleet_krkn [62]3 years ago

7 0

Answer:

141.4 centimeters

Step-by-step explanation:

circumference = diameter * pi c = d * pi c = 45 * 3.1416 c = 141.4 (rounded)

LiRa [457]3 years ago

7 0

Answer:

C= 141.37

Step-by-step explanation: go0gle

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2 years ago

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3 years ago

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A square steel bar has a length of 5.1 ft and a 2.7 in by 2.7 in cross section and is subjected to axial tension. The final leng

Andrej [43]

Answer:

The Poisson's ratio for the material is 0.0134.

Step-by-step explanation:

The Poisson's ratio ( $\nu$ ), no unit, is the ratio of transversal strain ( $\epsilon_{t}$ ), in inches, to axial strain ( $\epsilon_{a}$ ), in inches:

$\nu = -\frac{\epsilon_{t}}{\epsilon_{a}}$ (1)

$\epsilon_{a} = l_{a,f}-l_{a,o}$ (2)

$\epsilon_{t} = l_{t,f}-l_{t,o}$ (3)

Where:

$l_{a,o}$ - Initial axial length, in inches.

$l_{a,f}$ - Final axial length, in inches.

$l_{t,o}$ - Initial transversal length, in inches.

$l_{t,f}$ - Final transversal length, in inches.

If we know that $l_{a,o} = 61.2\,in$ , $l_{a,f} = 61.235\,in$ , $l_{t,o} = 2.7\,in$ and $l_{t,f} = 2.69953\,in$ , then the Poisson's ratio is:

$\epsilon_{a} = 61.235\,in - 61.2\,in$

$\epsilon_{a} = 0.035\,in$

$\epsilon_{t} = 2.69953\,in - 2.7\,in$

$\epsilon_{t} = -4.7\times 10^{-4}\,in$

$\nu = - \frac{(-4.7\times 10^{-4}\,in)}{0.035\,in}$

$\nu = 0.0134$

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3 years ago

A broken faucet leaks 1 gallon of water every 1 and1/3 months the amount of months that pass m varies directly with the amount o

Simora [160]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{\underline{m} varies directly with the amount of gallons}\implies \stackrel{months}{m}=k\stackrel{gallons}{g}
\\\\\\
\textit{we also know that }
\begin{cases}
m=1\frac{1}{3}\\
\qquad \frac{4}{3}\\
g=1
\end{cases}\implies \cfrac{4}{3}=k1\implies \cfrac{4}{3}=k
\\\\\\
\boxed{m=\cfrac{4}{3}g}\\\\
-------------------------------\\\\
\textit{what's \underline{m} when g=7?}\qquad m=\cfrac{4}{3}\cdot 7\implies m=\cfrac{28}{3}\implies m=9\frac{1}{3}$

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3 years ago

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emmasim [6.3K]

The answer is C) 9/35.

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2 years ago