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Kazeer [188]
2 years ago
6

Evaluate 13 + 6/y when y = 6

Mathematics
2 answers:
Radda [10]2 years ago
6 0

Answer:

14

Step-by-step explanation:

13 + 6/y

13 + 6/(6)

13 + 1

14

DIA [1.3K]2 years ago
4 0

Answer: 14

Step-by-step explanation: According to PEMDAS you do division first so if y=6 then you do 6/6=1. Then add 13+1

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Solve for x <br> solve for x <br> solve for x
goldenfox [79]

Answer:

x = 95

Step-by-step explanation:

(2x - 60)° = (x + 35)° (corresponding angles are congruent)

2x - 60 = x + 35

2x - 60 - x = x + 35 - x

x - 60 = 35

x - 60 + 60 = 35 + 60

x = 95

5 0
3 years ago
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Jon weighs 148 lbs and hopes to gain 2 lbs a week. Matt weighs 193lbs and hopes to lose 1 lb a week. How many weeks until they w
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It would take 15 weeks and they would meet at 178lbs.
6 0
3 years ago
Can someone answer this questions please answer it correctly if it’s correct I will mark you brainliest
muminat

Answer:

c

Step-by-step explanation:

0.1=1/10

1/10 is just the fraction form of 0.1

3 0
3 years ago
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What is the slope of the line that passes through the points (0,6) and (4,-1)
wlad13 [49]
To find the slope between the points, you would go through this process
(-1-6)/(4-0)
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(-7)/4
Aka
-(7/4) which is our slope
3 0
3 years ago
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0
1 year ago
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