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alisha [4.7K]
3 years ago
9

Greater than or less than the base?

Mathematics
1 answer:
yarga [219]3 years ago
4 0

Answer:

I think grater then?

Step-by-step explanation:

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R varies inversely as v2 if r=120 when v=1 ,find r when v=10
makvit [3.9K]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ r = k/v^2

Substitute the values in:

120 = k/1^2

Multiply both sides by 1^2 to find k

k = 120

Substitute new values in:

r = 120/10^2

Solve:

r = 1.2

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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6 0
3 years ago
For each relation, decide whether or not it is a function<br>​
Digiron [165]

Answer:

Relation 1,2,and 4 are functions, but relation 3 not is a function.

Step-by-step explanation:

function 1 input, no function with the same input like m in relation 3.

5 0
3 years ago
A movie theater charges $8.50 for an adult ticket to an evening showing of a popular movie. To help the local animal shelter, th
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Answer: What’s the answer ?

Step-by-step explanation:

6 0
3 years ago
Two cards are drawn without replacement from a well-shuffled deck of 52 playing cards. what is the probability that the first ca
GarryVolchara [31]
Total number of cards = 52
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Number of cards that is not a club = 39

P(club + not a club) = (13/52) (39/51) = 13/68

Answer: 13/68
5 0
3 years ago
I need help learning how to solve this problem please.
Radda [10]

we have 4 gals, Stephanie, Andrea, Emily and  Becca.

btw the end point should be (-6, -7) and the start point is (8, 6).

so, if we know the distance between those two points, we can just cut it in 4 equal pieces and each gal will be driving a piece.

now, Emily's turn is after Andrea, BUT, we had first Stephenie driving ¼ of the way, then Andrea driving ¼ of the way too, but after ¼+¼, Emily comes on, but ¼+¼ is really 1/2, so when Emily starts, is really half-way through, or the midpoint of that distance.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\stackrel{\textit{Hometown}}{(\stackrel{x_1}{8}~,~\stackrel{y_1}{6})}\qquad&#10;\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}&#10;\qquad&#10;\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-6+8}{2}~~,~~\cfrac{-7+6}{2} \right)\implies \left(\cfrac{2}{2}~,~\cfrac{-1}{2} \right)\implies \stackrel{\textit{Emily starts off}}{\left(1~,-\frac{1}{2} \right)}


Emily's turn ends ¼ of the way later, which will be pretty much half-way in between  (1, -½) and (-6, -7), so is really the midpoint of those two.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;(\stackrel{x_1}{1}~,~\stackrel{y_1}{-\frac{1}{2}})\qquad&#10;\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}&#10;\\\\\\&#10;\left( \cfrac{-6+1}{2}~~,~~\cfrac{-7-\frac{1}{2}}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-14-1}{2}~}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-15}{2}~}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-5}{2}~,~\cfrac{-15}{4} \right)\implies \left( -2\frac{1}{2}~,~-3\frac{3}{4} \right)

8 0
4 years ago
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