Helpppp pleaseeeee summer school needs done

What is the equation of a horizontal line that has a y-intercept of 3.5?

beks73 [17]

First, recall that the equation of a line is

y = mx+b

where

m = slope
b = y-int

The key to this question is the details :

Horizontal line ---> This tells you that your slope is 0

y-int = 3.5 -----> In the equation above, b=3.5

Therefore,

y = 0x + 3.5
y = 0 + 3.5
y = 3.5

4 0

3 years ago

9 < 4(x+9) -7 - 25<br> Solve , intervals, and graph

Zigmanuir [339]

Answer:

x> 5/4

Step-by-step explanation:

9<4(x+9)−7−25

Step 1: Simplify both sides of the inequality.

9<4x+4

Step 2: Flip the equation.

4x+4>9

Step 3: Subtract 4 from both sides.

4x+4−4>9−4

4x>5

Step 4: Divide both sides by 4.

4x/4>5/4

x>5/4

pls give brainliest

5 0

3 years ago

Can somebody help me?

True [87]

Answer:

7-(-2)=7+2

Step-by-step explanation:

7-(-2)=9

7+2=9

Hope this helps!

6 0

3 years ago

Week 1 2 3 4 5 Water Level (inches) − 1 1 4 1 3 8 2 1 2 − 1 5 8 − 1 3 4 Between which two weeks did the water level change the m

suter [353]

Answer:

The water level change the most in week 3 and week 4

The change = -370 inches

Step-by-step explanation:

Given - Week 1 2 3 4 5

Water Level (inches) − 1 1 4 1 3 8 2 1 2 -1 5 8 -1 3 4

To find - Between which two weeks did the water level change the most? Calculate the change .

Proof -

The formula for change in water level with respect to week be-

Rate of Change in Water Level = Difference in water level / Difference in weeks

Now,

For week 1 and week 2

Rate of change in water level = $\frac{138 - 114}{2 - 1}$ = $\frac{24}{1}$ = 24 inches

Now,

For week 1 and week 3

Rate of change in water level = $\frac{212 - 114}{3 - 1}$ = $\frac{98}{2}$ = 49 inches

Now,

For week 1 and week 4

Rate of change in water level = $\frac{-158 - 114}{4 - 1}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 1 and week 5

Rate of change in water level = $\frac{-134 - 114}{5 - 1}$ = $-\frac{248}{4}$ = -62 inches

Now,

For week 2 and week 3

Rate of change in water level = $\frac{212 - 138}{3 - 2}$ = $\frac{74}{1}$ = 74 inches

Now,

For week 2 and week 4

Rate of change in water level = $\frac{-158 - 138}{4 - 2}$ = $-\frac{296}{2}$ = -148 inches

Now,

For week 2 and week 5

Rate of change in water level = $\frac{-134 - 138}{5 - 2}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 3 and week 4

Rate of change in water level = $\frac{-158 - 212}{4 - 3}$ = $-\frac{370}{1}$ = -370 inches

Now,

For week 3 and week 5

Rate of change in water level = $\frac{-134 - 212}{5 - 3}$ = $-\frac{346}{2}$ = 173 inches

Now,

For week 4 and week 5

Rate of change in water level = $\frac{-134 + 158}{5 - 4}$ = $\frac{24}{1}$ = 24 inches

∴ we get

The water level change the most in week 3 and week 4

The change = -370 inches

Note :

The highest change means which temperature goes the most change in water level. It can be negative also.

So, We have to take the modulus and then find the highest number.

Here, 370 > 173

So, Highest change occurs in Week 3 and Week 4 but not in Week 3 and Week 5.

7 0

3 years ago

$200 at 15.5% for 2 years

Inessa05 [86]

15.5 I believe but don’t hold me to it!

8 0

3 years ago