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makvit [3.9K]
3 years ago
11

Use the table to find the relationship between the two quantities.

Mathematics
2 answers:
olchik [2.2K]3 years ago
3 0

Answer:

the answer is 3

Step-by-step explanation:

Alenkinab [10]3 years ago
3 0

Answer:

3

Step-by-step explanation:

edg 2021

i did the assignment a few minutes ago and made a 100 hope u have a great day and make sure to wear a mask and drink lots of water! ^^

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Find the y-intercept of the graph of the linear equation. 3/4 x + y = 10
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Which shows the following expression after the negative exponents have been eliminated?
Mazyrski [523]

Answer:

a^2b^2

Step-by-step explanation:

Given the algebraic expression:

\dfrac{a^3b^{-2}}{ab^{-4}} , a\neq 0, b\neq 0

We are required to eliminate the negative exponents and find the resulting expression.

Using the Negative Exponent Law of Indices: x^{-y}=\dfrac{1}{x^y}

Using the Division Law of Indices: \dfrac{t^x}{t^y}=t^{x-y}

Therefore:

\dfrac{a^3b^{-2}}{ab^{-4}} = a^{3-1}\cdot b^{-2-(-4)}\\$Simplifying\\a^{3-1}\cdot b^{-2-(-4)}=a^2b^{-2+4}\\=a^2b^2\\Therefore:\\\dfrac{a^3b^{-2}}{ab^{-4}}=a^2b^2

7 0
3 years ago
Read 2 more answers
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