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Volgvan
1 year ago
7

Could I have some help on my patterns assignment​

Mathematics
1 answer:
nydimaria [60]1 year ago
8 0

Answer:

1. 13, 18, 23, 28, 33, 38, 43, 48, 53

<em>Conjecture:</em> Each term is 5 more than the previous term.

2. 512, 256, 128, 64, 32, 16, 8, 4, 2

<em>Conjecture:</em> Each term is half of the previous term.

3. 1, 8, 27, 64, 125, 216, 343, 512, 729

<em>Conjecture:</em> Each term is a cube. To find the nth term, cube n.

4. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

<em>Conjecture:</em> Each term is the next consecutive prime number.

5. <u><em>Correct as is</em></u>

6. 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89

<em>Conjecture:</em> Each term is the sum of the 2 previous numbers.

Step-by-step explanation:

1.

Given: 13, 18, 23, 28

<em>We add 5 to each number</em>

13 + 5 = 18

18 + 5 = 23

23 + 5 = 28

28 + 5 = 33

33 + 5 = 38

38 + 5 = 43

43 + 5 = 48

48 + 5 = 53

2.

Given : 512, 256, 128, 64

<em>Divide each number by 2</em>

512 ÷ 2 =256

256 ÷ 2 = 128

128 ÷ 2 = 64

64 ÷ 2 = 32

32 ÷ 2 = 16

16 ÷ 2 = 8

8 ÷ 2 = 4

4 ÷ 2 = 2

3.

Given: 1, 8, 27, 64

<em>We have to cube n:</em>

<u><em>n³ = consecutive number cubed</em></u>

<u><em></em></u>

1³ = 1 or 1 × 1 × 1

2³ = 8 or 2 × 2 × 2

3³ = 27 or 3 × 3 × 3

4³ = 64 or 4 × 4 × 4

5³ = 125 or 5 × 5 × 5

6³ = 216 or 6 × 6 × 6

7³ = 343 or 7 × 7 × 7

8³ = 512 or 8 × 8 × 8

9³ = 729 or 9 × 9 × 9

4.

Consecutive prime number: <u><em>Consecutive prime numbers are those that have no gaps or prime numbers between them.</em></u>

Look at the picture in the link:

6.

Given: 1, 1, 2, 3, 5, 8

<em>We must add the two previous numbers to get the next term:</em>

1 + 1 = 2

1 + 2 = 3

2 + 3 = 5

3 + 5 = 8

5 + 8 = 13

8 + 13 = 21

13 + 21 = 34

21 = 34 = 55

34 + 55 = 89

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3 years ago
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If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes
Keith_Richards [23]
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
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+
88
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(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
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This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
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The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f (
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Complete  Question

The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f ( t ) represents the cost (in dollars) of a new Honda Accord t years after 2000. Use function notation to represent each of the following. The cost (in dollars) of a new Accord in 2006?

A. How much more a new Accord costs in 2013 as compared to the cost of a new Accord in 2010?

B. A new Accord in 2013 is how many times as expensive as a new Accord in 2010?

C. In  2016 , some cars cost  $980 more than the cost of a new Accord.How much does the other cars cost (in dollars)in 2016?

Answer:

a

     The cost of  a new Accord in 2013 compared to 2010 is  z  =  f(13) -  f(10)

b

   The magnitude at which the cost of   a new Accord in 2013 is greater          than the cost in 2010 is  

          x =  \frac{f(13)}{f(10)}

c

    The cost of the other cars is 2016 is   r  =  980 + f(16)

Step-by-step explanation:

From the question we are told that

     The cost (in dollars) of a new Honda Accord is  f(t)

       Where t is  number of years after 2000

The cost of the  Honda Accord at 2013 is  

        f(2013 - 2000) =  f(13)

The cost of the  Honda Accord at 2010 is  

        f(2010 - 2000) =  f(10)

So the cost difference between 2013 and 2010 is mathematically evaluated as

         z  =  f(13) -  f(10)

Let constant at which the cost of Honda Accord in 2013 is greater than its cost at 2010 be  x

So

      f(13) =  x f(10)

=>      x =  \frac{f(13)}{f(10)}

  The cost of the Honda Accord in 2016 is mathematically evaluated as

          f(2016 - 2000) =   f(16)    

Now the cost of these other cars is  mathematically evaluated as  

         r  =  980 + f(16)

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