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3 years ago

8

What is ____ divided 12 = 3? What is the answer to the blank?

2 answers:

dalvyx [7]3 years ago

7 0

$x- unknown\\\\\ \frac{x}{12}=3\ \ |*12\\\\x=3*12\\\\x=36\\\\ Unknown\ number\ is\ equal\ to\ 36.$

Ksivusya [100]3 years ago

5 0

$x:12=3\to x=3\times12=36\\\\Answer:\\36:12=3$

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Patrick built a robot that is 0.8 meters tall. Adelaide built a robot that is 2 feet and 9 inches tall. Who has the taller robot

Ugo [173]

Answer:

Adelaide's robot is 83.82 centemetres = 0.84 meters

Step-by-step explanation:

2 feet = 60.96cm + 9 inches = 22.86cm therefore Adelaide's robot is taller

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2 years ago

Greek city-states began to form in 800 B.C. and in 200 A.D, Christians began getting persecuted. How many years passed between t

asambeis [7]

Answer: 1000 years

Step-by-step explanation:

-Greek city-states began to form in 800 B.C i.e 800 years Before Christ appearance

- up till 200 A.D i.e 200 years of After Christ disappearance

Hence, the number of years between the time that Greek city-states began to form and the persecution of Christians began is equal to the sum of years Greek city States started formation and Year persecution began

i.e 800 BC + 200 A.D = 1000 Years

Thus, the number of years of that passed was 1000 years

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3 years ago

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3 years ago

Solve 2x + 3y = C, for y

natta225 [31]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

2 years ago