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3 years ago

Find the area of the

Mathematics

1 answer:

Ugo [173]3 years ago

8 0

Answer:

E. 443.4 ft²

Step-by-step explanation:

Since it is a regular triangle, it means all three sides are of equal lengths and all angles are of the same degree measure.

Therefore, all sides = 32 ft each

Each equal angle = 60° (sum of all angles = 180)

The area of the triangle can be calculated using the formula, ½*a*b*sin(C),

Where,

a = 32 ft

b = 32 ft

C = 60°

Plug in the values

Area = ½*32*32*Sin(60)

Area = 443.4 ft² (nearest tenth)

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Answer:

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Jerome is going to draw a marble from the bag shown below, replace it, and then draw another marble. What is the probability tha

alexira [117]

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3 years ago

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A multiplier of 1.641 corresponds to a percentage increase or decrease of what percent?

bezimeni [28]

Answer:

A multiplier of 1.641 corresponds to a percentage increase or decrease of 64.1%.

Step-by-step explanation:

To determine a percentage increase or decrease of a certain number, a calculation consisting of the multiplication of said number by 1 plus the decimals corresponding to the percentage to be increased must be performed. Thus, for example, if you want to increase a number by 50%, you must multiply that number by 1.50. Therefore, if you multiply a number by 1,641, this implies that you are wanting to increase or decrease the initial number by 64.1%.

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3 years ago

Please help asap!! Is this correct? If not can I please have some help.

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Answer:

Yes, that is correct.

Step-by-step explanation:

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3 years ago

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle

taurus [48]

Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

we have been asked to find the ratio of the radius of circle Q to the radius of circle R?

As we know that

Area of the sector is directly proportional to square of radius. So we can write

$Area \ \ \alpha \ \ r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\ \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\ \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\ \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\ \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\$

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3 years ago

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