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3 years ago

What is the completely factored form of p4 - 16?

Mathematics

1 answer:

il63 [147K]3 years ago

8 0

The completely factored form of p^4-16 is:

$(p^2+4)(p+2)(p-2)$

Step-by-step explanation:

We have to factorize the given expression to get the final result

Given

$p^4-16\\Using\ Formula: a^2-b^2=(a+b)(a-b)\\(p^2)^2-(4)^2\\=(p^2+4)(p^2-4)$

p^2-4 can further be factored again

$=(p^2+4)[(p)^2-(2)^2]\\=(p^2+4)(p+2)(p-2)$

The completely factored form of p^4-16 is:

$(p^2+4)(p+2)(p-2)$

Keywords: Factorization

Learn more about factorization at:

#LearnwithBrainly

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Gre4nikov [31]

Answer:

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Step-by-step explanation:

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3 years ago

Square root of 32 x square root of 1 over 18

lisov135 [29]

<h3>Solution:</h3>

$\sqrt{32} \times \sqrt{ \frac{1}{18} } \\ = \sqrt{32} \times \frac{ \sqrt{1} }{ \sqrt{18} } \\ = \sqrt{32} \times \frac{1}{ \sqrt{18} } \\ = \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} } \\ = \frac{ \sqrt{ {2}^{2} \times {2}^{2} \times 2} }{ \sqrt{2 \times {3}^{2} } } \\ = \frac{2 \times 2 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4}{3}$

<h3>Answer:</h3>

$\frac{4}{3}$

<h3>Hope it helps...</h3>

ray4918 here to help

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3 years ago

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Mumz [18]

Answer:

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Step-by-step explanation:

1=c

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I know 1 and 2 are correct, but I am not sure about the others

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AURORKA [14]

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