A mixture contains forty ounces of glycol and water and is ten percent glycol. If the mixture is to be strengthened to twenty-fi

Question

2 years ago

11

ve percent, how much glycol is to be added?
4 oz
8 oz
10 oz

2 answers:

irina1246 [14] · Answer 1 · 2022-05-24T09:49:19+03:00

7 0

10(40) + x = .25(x + 40)

4 + x = .25x + 10

x - .25x = 10 - 4

.75x = 6
x =
x = 8 oz of glycol required

telo118 [61] · Answer 2 · 2022-05-24T07:30:19+03:00

4 0

If we add 8 oz of glycol to the 40 oz mixture we have 48 oz of mixture and 4+8 = 12 oz glycol
12 / 48 = 1/4 = 25 % glycol

the answer is 8 oz