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sergij07 [2.7K]
3 years ago
11

A mixture contains forty ounces of glycol and water and is ten percent glycol. If the mixture is to be strengthened to twenty-fi

ve percent, how much glycol is to be added?
4 oz
8 oz
10 oz
Mathematics
2 answers:
irina1246 [14]3 years ago
7 0
10(40) + x = .25(x + 40)
 
4 + x = .25x + 10
 
x - .25x = 10 - 4
 
.75x = 6
x =
x = 8 oz of glycol required
telo118 [61]3 years ago
4 0
If we add 8 oz of glycol to the 40 oz mixture we have 48 oz of mixture and 4+8 = 12 oz glycol
 12 / 48  = 1/4   = 25 % glycol 

the answer is 8 oz
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