At EHS, a football player ran a total of 1,032 yards in 12 games. If the rate stays the

In detail explain how to multiply in binomial of (5x-7 (2x-1) in foil method

Nesterboy [21]

Step-by-step explanation:

First

Outer

Inner

Last

First- 5x*2x=10x^2

Outer-5x*-1= -5x

Inner--7*2x= -14x

Last- -7*-1= 7

10x^2-5x-14x+7

you can simplify it further however thats the answer

4 0

2 years ago

Identify the interval on which the quadratic function is positive.

Alenkasestr [34]

Answer:

$\textsf{1. \quad Solution: $1 < x < 4$,\quad Interval notation: $(1, 4)$}$

$\textsf{2. \quad Solution: $-2 < x < 4$,\quad Interval notation: $(-2, 4)$}$

Step-by-step explanation:

<h3>Question 1</h3>

The intervals on which a quadratic function is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a negative leading coefficient, the parabola opens downwards. Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x-1=0 \implies x=1$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is positive is:

Solution: 1 < x < 4
Interval notation: (1, 4)

<h3>Question 2</h3>

The intervals on which a quadratic function is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a positive leading coefficient, the parabola opens upwards. Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x+2=0 \implies x=-2$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is negative is:

Solution: -2 < x < 4
Interval notation: (-2, 4)

3 0

10 months ago

Let ∠D be an acute angle such that sinD=0.19. Use a calculator to approximate the measure of ∠D to the nearest tenth of a degree

maxonik [38]

Answer:

D = pi+2 sin omega /3cos0

Step-by-step explanation:

18+3930

3 0

3 years ago

Please help asap! its needed badly

Ilya [14]

Answer:

can u retake the photo

Step-by-step explanation:

5 0

3 years ago

Can Miguel use 3/4 inch strips to make a line that is exactly 5 inches long.Explain

Sliva [168]

No:
0.75+0.75=1.5
1.5+0.75=2.25
2.25+0.75=3.00
3.00+0.75=3.75
3.75+0.75=4.50
4.50+0.75=5.25

3 0

3 years ago