The formula for volume of a sphere is V = 4
/3 x π x r3 (cubed).
The original radius of the balloon is 10 ft, so when we plug that value into the equation we get 4188.79. When the balloon deflated, the new radius was 5 ft, so the new volume is 523.6. The question asks how much volume was lost, so we need to subtract 4188.79 - 523.6 and get approximately 3665.
Hope this helps! I hate taking usa test prep quizzes too haha.
They are all cold, they're below freezing in both C and F, they're impossible temperatures in K, and from a math standpoint they have a mean of approximately 2.7 ish, the median is -2, the mode is nonexistent, you don't have enough data points to do quartiles, the max is -1 and the min is -5. I hope this helpful
Answer:
Not necessarily, because this wasn't an experiment.
Step-by-step explanation:
Answer:
(-3 + -2y)(5 + -1y) = 0
Step-by-step explanation:
Simplifying
(y + -5)(2y + 3) = 0
Reorder the terms:
(-5 + y)(2y + 3) = 0
Reorder the terms:
(-5 + y)(3 + 2y) = 0
Multiply (-5 + y) * (3 + 2y)
(-5(3 + 2y) + y(3 + 2y)) = 0
((3 * -5 + 2y * -5) + y(3 + 2y)) = 0
((-15 + -10y) + y(3 + 2y)) = 0
(-15 + -10y + (3 * y + 2y * y)) = 0
(-15 + -10y + (3y + 2y2)) = 0
Combine like terms: -10y + 3y = -7y
(-15 + -7y + 2y2) = 0
Solving
-15 + -7y + 2y2 = 0
Solving for variable 'y'.
Factor a trinomial.
(-3 + -2y)(5 + -1y) = 0
