Step-by-step explanation:
![Given \: speed \: = 160km| h \\ To \: find \: speed \: in \: m|s \\ Solution \: speed \: = 160km|h \\ = (160 \times \frac{5}{18}) \: m|s \\ = \frac{800}{18} m|s \\ = 44.44m|s \\ Hence \: speed \: = 44.44m|s...](https://tex.z-dn.net/?f=Given%20%5C%3A%20speed%20%5C%3A%20%20%3D%20160km%7C%20h%20%20%5C%5C%20To%20%5C%3A%20find%20%5C%3A%20speed%20%5C%3A%20in%20%5C%3A%20m%7Cs%20%5C%5C%20Solution%20%5C%3A%20speed%20%5C%3A%20%20%3D%20160km%7Ch%20%5C%5C%20%20%3D%20%28160%20%5Ctimes%20%5Cfrac%7B5%7D%7B18%7D%29%20%5C%3A%20m%7Cs%20%5C%5C%20%20%3D%20%20%5Cfrac%7B800%7D%7B18%7D%20m%7Cs%20%5C%5C%20%20%3D%2044.44m%7Cs%20%5C%5C%20Hence%20%5C%3A%20speed%20%5C%3A%20%20%3D%2044.44m%7Cs...)
<em>hOpE</em><em> </em><em>iT</em><em> </em><em>hElPs</em><em> YoU</em>
<h3><em><u>I</u></em><em><u> </u></em><em><u>nEEd</u></em><em><u> bRainLIeST</u></em></h3>
Let K = the number of teeth Kathleen lost
C=K-4
The test statistic, rounded to 2 decimal places is equal to
<h3>How to calculate value of the test statistic?</h3>
For this sample, the hypothesis is given by:
H₀: μ₁ ≤ μ₂
H₁: μ₁ > μ₂
Assuming this sample has a normal distribution, we would use a pooled z-test to determine the value of the test statistic:
Substituting the given parameters into the formula, we have;
![z = \frac{\frac{96}{150} \;-\;0.63}{\sqrt{0.63\; +\; \frac{1\;-\;0.63}{150}} }\\\\z = \frac{0.64 \;-\;0.63}{\sqrt{0.63\; +\; \frac{0.37}{150}}}\\\\z = \frac{0.01}{\sqrt{0.63\; +\; 0.0025}}\\\\z = \frac{0.01}{\sqrt{0.6325}}\\\\](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B%5Cfrac%7B96%7D%7B150%7D%20%5C%3B-%5C%3B0.63%7D%7B%5Csqrt%7B0.63%5C%3B%20%2B%5C%3B%20%5Cfrac%7B1%5C%3B-%5C%3B0.63%7D%7B150%7D%7D%20%7D%5C%5C%5C%5Cz%20%3D%20%5Cfrac%7B0.64%20%5C%3B-%5C%3B0.63%7D%7B%5Csqrt%7B0.63%5C%3B%20%2B%5C%3B%20%5Cfrac%7B0.37%7D%7B150%7D%7D%7D%5C%5C%5C%5Cz%20%3D%20%5Cfrac%7B0.01%7D%7B%5Csqrt%7B0.63%5C%3B%20%2B%5C%3B%200.0025%7D%7D%5C%5C%5C%5Cz%20%3D%20%5Cfrac%7B0.01%7D%7B%5Csqrt%7B0.6325%7D%7D%5C%5C%5C%5C)
z = 0.01/0.7953
z = 0.013.
Read more on test statistic here: brainly.com/question/14839648
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Sum of (+) 4 times the number p and six (4p+6) is (=) 46 (46)
4p+6=46
subtract 6 from both sides
4p=40
divide by 4
p=10