One simple way to approach this is to subtract the number that DOESN’T have the variable with the solution by the sum.
Lets use problem 1 as the example:
1.) N+8=13
In this case, we subtract 13 by 8 and get 5, therefore N= 5.
2.) B+17=62
62-17= 45
B= 45
3.) X+5/6= 7/16
7/16-5/6= -19/48
X= -19/48
4.) y+1/7=5/8
5/8-1/7= 27/56
Y= 27/56
5.) 14+y=69
69-14=55
Y=55
6.) c+3.6=4.9
4.9-3.6=1.3
C= 1.3
Now for the word problems:
Lets use 7 as the example-
7.) a number increased by 19 is equal to 221.
Since we don’t know the number being increased by 19, that will be our variable. It will be re-written as so:
N + 19 = 221
Where N is the unknown number.
Using the same method of subtracting by the sum and the number that’s not the variable, we’ll get the solution to N
221-19= 202
N= 202
8.) N + 1 2/3 = 8
8 - 1 2/3 = 19/3= 6 1/3
N= 6 1/3
I really hope this helps
#1 divide by 6n to both sides to get n by itself
#2 multiply both sides by 6/5a to get a by itself
#3 multiply both sides by 2/5x to get x by itself
When you have whole numbers (no decimals) you can divide. When you have numbers with decimals, convert them to fractions and multiply by the reciprocal to get the variable by itself.
Answer:
Popcorn costs: $5.75, and drink costs: $2.25.
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
Answer:
r]
Step-by-step explanation:
