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2 years ago

If the ratio of boys to girls at the school is 2:5 and there are 40 boys how many girls are there?

Mathematics

1 answer:

sukhopar [10]2 years ago

5 0

Answer:

100 girls

Step-by-step explanation:

The ratio of boys : girls is 2 : 5.

In other words, boys are 2 parts of the school while girls are 5 parts of the school.

Since there are 40 boys, 2 parts of the school is 40. Thus:

$2p = 40\\p = 20$

1 part is 20.

Since there are 5 parts girls, there are

$5p = 5*20 = 100$

100 girls.

Answer: 100 girls

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Which function f (x) , graphed below, or g (x) , whose equation is g (x) = 3 cos 1/4 (x + x/3) + 2, has the largest maximum and

Leya [2.2K]

Answer:

g(x), and the maximum is 5

Step-by-step explanation:

for given function f(x), the maximum can be seen from the shown graph i.e. 2

But for the function g(x), maximum needs to be calculated.

Given function :

g (x) = 3 cos 1/4 (x + x/3) + 2

let x=0 (as cosine is a periodic function and has maximum value of 1 at 0 angle)

g(x)= 3 cos1/4(0 + 0) +2

= 3cos0 +2

= 3(1) +2

= 3 +2

= 5 !

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2 years ago

What is the decimal of 32/100

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Answer:

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Step-by-step explanation:

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3 years ago

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2 years ago

Read 2 more answers

Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants

musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error for the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.22$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample should she take?

We need a sample size of at least n.

n is found when $M = 0.02$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}$

$\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}$

$n = 1160.88$

Rounding up

We need a sample size of at least 1161.

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3 years ago

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Answer:

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Step-by-step explanation:

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