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3 years ago

Problem: Prove that the quadrilateral defined by the points F(6,4), R(1,3), O(3,2), G(−2,1) is a parallelogram.

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

8 0

Answer:

Answer:

114 cm²

Step-by-step explanation:

Area of shaded region

= area of circle -area of square

\boxed{area \: of \: circle = \pi {r}^{2} }

areaofcircle=πr

Given that radius= 10cm, r= 10cm.

\boxed{area \: of \: square = side \: \times side}

areaofsquare=side×side

Let the length of a side of the square be x cm.

Applying Pythagoras Theorem,

10² +10²= x²

100 +100= x²

x²= 200

x = \sqrt{200}x=

200

Area of square

= x²

= 200cm²

Area of shaded region

= 3.14(10²) -200

= 3.14(100) -200

= 314 -200

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3 years ago

If h(x) = 2x4 - 4x2 - 2x, then h(3)= ? A) -6 B) 120 C) 192 D) 1146 E) 1434

garik1379 [7]

The value of h(3) is 120 ⇒ B

Step-by-step explanation:

To find the value of f(x) at x = a, do that

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4 years ago

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3 years ago

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Marta_Voda [28]

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Step-by-step explanation:

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Now she needs to divide both sides of the equation by $2\pi r$ , then:

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Rewriting:

$h=\frac{s}{2\pi r}-\frac{2\pi r^2}{2\pi r}$

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4 years ago

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Problem: ​Prove that the quadrilateral defined by the points F(6,4), R(1,3), O(3,2), G(−2,1) is a parallelogram.

Problem: Prove that the quadrilateral defined by the points F(6,4), R(1,3), O(3,2), G(−2,1) is a parallelogram.