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vovikov84 [41]
3 years ago
14

GEOMETRY PROBLEM HELP ME PLEASE

Mathematics
2 answers:
Anon25 [30]3 years ago
6 0

Answer:

18. x=31

19.x=15

20. a. x=5 WXY= 28

b. YXZ=28

c. WXZ=56

aleksandr82 [10.1K]3 years ago
3 0
Here you go!! I hope this helps

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Solve the equation for x. 2x + 22 = 4(x+3)
shusha [124]

Answer:

x = 5

Step-by-step explanation:

We have the algebraic expression and are asked to solve for x.

To solve, we need to isolate x.

2x + 22 = 4(x + 3)

Distribute :

2x + 22 = (4(x) + 4(3))

2x + 22 = 4x + 12

Subtract 12 from both sides :

2x + 10 = 4x

4x = 2x + 10

Subtract 2x from both sides :

2x = 10

Divide 2 from both sides to get x alone :

x = 5

5 0
3 years ago
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How many ways can a rectangle be reflected across an axis of symmetry so that it carries onto itself?
anastassius [24]
I believe the correct answer from the choices listed above is option B. A rectangle can be reflected across an axis of symmetry so that it carries onto itself twice. <span>Rectangles are geometric shapes with </span>two lines<span> of symmetry. One line of symmetry divides a rectangle in half horizontally, and the other line divides the shape in half vertically.</span>
8 0
3 years ago
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How to set the answer up
Korolek [52]

Let s and g represents the numbers of suits and gowns produced.

The number of zippers used is 2s+g.

The number of buttons used is 5s+8g.

In order to use all of the available zippers and buttons, we must have ...

  • 2s + g = 171
  • 5s + 8g = 576

Cramer's rule tells you the solution to the system

  • ax +by = c
  • dx +ey = f

Is given by

  • x = (bf-ey)/(bd-ea)
  • y = (cd-fa)/(bd-ea)

Using this rule on the equations for zippers and buttons, we have

... s = (1·576 -8·171)/(1·5 -8·2) = -792/-11 = 72

... g = (171·5 -2·576)/-11 = -297/-11 = 27

72 suits and 27 gowns can be made from available zippers and buttons.

3 0
4 years ago
How do I solve numbers 8 and 9?
Tresset [83]
8: 20
9: 90
I am so sorry if this is wrong. I am not good at this type of things
7 0
2 years ago
10 POINTS! PLEASE HELP!! The illustration shows a compact disc tray that holds five CDs. The radius of each compact disc is 9 cm
MariettaO [177]

We can see that there are 5 CDs, each of radius 9 cm

<u>Area occupied by 1 disc:</u>

Area of a circle = πr²

Area of disc = π(9)²

Area of disc = 3.14 * 81 = 254 cm²

<u>Area occupied by 5 discs:</u>

Area occupied by 5 discs = Area occupied by 1 disc * 5

Area occupied by 5 discs = 254 * 5

Area occupied by 5 discs = 1270 cm²

3 0
3 years ago
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