Answer:
The answer is stratified.
Step-by-step explanation:
y - 5 = 3/2(x + 3)
y - 5 = 3/2x + 9/2
y = 3/2x + 9/2 + 5
y = 3/2x + 19/2
<em>Equation</em><em> </em><em>of</em><em> the</em><em> line</em><em> </em><em>formula</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>mx</em><em> </em><em>+</em><em> </em><em>c</em>
<em>#</em><em>S</em><em>o</em><em> </em><em>the</em><em> </em><em>slope</em><em> </em><em>(</em><em>m</em><em>)</em><em> </em><em>is</em><em> </em><em>3</em><em>/</em><em>2</em>
<h2>
<em>Answer</em><em> </em><em>:</em><em> </em><em>3</em><em>/</em><em>2</em></h2>
Answer:
i dont think so
Step-by-step explanation:
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
Learn more about the area of rectangle here:
brainly.com/question/15019502
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