Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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1 yard is 3ft, so just multiply 2.5 with 3 and that gives u 7.5.
Answer:
2.1578
Step-by-step explanation:
<h3><u>Answer :- </u></h3>
- The total surfAce area of cone is <u>1244.57m².</u>
<h3><u>Step-by-step</u><u> </u><u>explanation</u><u> </u><u>:</u><u>-</u><u> </u></h3>
<u>To </u><u>find </u><u>:</u><u>-</u><u> </u>
- The total surface area of cone..
<h3><u>Solution :- </u></h3>
Given that ,
- The slant height of the cone = 21m.
- Diameter of it's base = 24m.
<h3><u>♦</u><u> </u><u>Radius is </u></h3>
<u>=</u>> Diameter / 2
=> 24 / 2
=> 12m
<h3>As we know that , </h3>
<u>Total surface area of cone = πr ( r + L ) .</u>
<h3><u>Where</u><u> </u><u>we </u><u>know</u><u>,</u></h3>
- π = 22/7
- r = Radius ( radii )..
- L = Slant height.
<h3>According to the question :- </h3>
The total surface of cone is,
<u>=> Total surface area = πr { r + L } ..</u>






• Therefore , The total surface area of cone is <u>1244.57m².</u>
Hope this helps you :)
Answer:
20,667.
Step-by-step explanation:
This is an arithmetic series:
3 + 9 + 15 + 21 + 27+ ...........+ 495
First term = 3 and common difference = 6.
Number of terms = ( 495 - 3 )/6 + 1
= 83.
So Sn = n/2(a1 + l) where a1 = first term and l = last term
S83 = 83/2(3 + 495)
= 41.5 * 498
= 20,667.