Answer:
Step-by-step explanation:
Assuming a normal distribution for the distribution of the points scored by students in the exam, the formula for normal distribution is expressed as
z = (x - u)/s
Where
x = points scored by students
u = mean score
s = standard deviation
From the information given,
u = 70 points
s = 10.
We want to find the probability of students scored between 40 points and 100 points. It is expressed as
P(40 lesser than x lesser than or equal to 100)
For x = 40,
z = (40 - 70)/10 =-3.0
Looking at the normal distribution table, the corresponding z score is 0.0135
For x = 100,
z = (100 - 70)/10 =3.0
Looking at the normal distribution table, the corresponding z score is 0.99865
P(40 lesser than x lesser than or equal to 100) = 0.99865 - 0.0135 = 0.98515
The percentage of students scored between 40 points and 100 points will be 0.986 × 100 = 98.4%
Answer:
just turn the percentage into a decimal then you multiply or add
Answer: Answers provided below in sequential order.
Step-by-step explanation: UV = 12(3)-1
(They said that x = 3)
UV = 35 (12*3-1)
70 = TV
TU = UV
8x + 11 = 12x - 1
-4x = 10
x = -10/4 or -5/2 (simplified)
TU = 8 (3) + 11
TU = 35 (24+11)
Answer:
Number of bags of candy = 2
Number of bags of cookies = 7
Step-by-step explanation:
Let, number of bags of candy = X
So, Number of bags of cookies = X + 5
Cost of candy bag = $8
Cost of cookies bag = $2.5
Total sales = $33.50
So, Total cost of Candy Bags + Total cost of cookies bags = Total sales
= 8X + 2.5 ( X +5) = 33.50
= 8X + 2.5X + 12.5 = 33.50
= 10.5X = 33.50 - 12.5
= 10.5X = 21
X = 2
So, number of bags of candy = 2
Number of bags of cookies = 2 + 5 = 7
