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irakobra [83]
3 years ago
8

......................

Mathematics
1 answer:
asambeis [7]3 years ago
3 0
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HELLPPPPP PLEASE!!!!! ILL MARK YOU BRAINLIEST
Keith_Richards [23]

Answer: four raised to the one third power

Step-by-step explanation:

According to the written description, we have the following expression:

\sqrt{\frac{4}{\sqrt[3]{4}}}

Which can also be written as:

(\frac{4}{4^{\frac{1}{3}}})^{\frac{1}{2}}

Let's work with this, taking into account the rules of multiplication and division of power with the same base:

(4^{1-\frac{1}{3}} )^{\frac{1}{2}}=(4^{\frac{2}{3}})^{\frac{1}{2}}

Multiplying the exponents:

4^{\frac{1}{3}} This is read as "four raised to the one third power"

6 0
3 years ago
Read 2 more answers
A crowd of 50,000 fans is expected to attend the homecoming football game. if the typical vendor can serve 1,500 customers per h
Andre45 [30]
One vendor can serve 1500 customers per hour. in 4 hours he can serve 6000 customers & we have to serve 50000 fans so for this purpose we need 50000 / 6000 that is 8.••• vendors so in short we need 9 vendors at all so they can serve all the 50000 fans

hope this helps. mark this is brainliest answer
5 0
3 years ago
Read 2 more answers
Need help what’s the correct answer for this question?
julsineya [31]

Answer:

8

Step-by-step explanation:

A scale factor of 4/5 means that each side length or distance is multiplied by 4/5. 10*4/5=8. Hope this helps!

6 0
3 years ago
Which sum or difference is modeled by the algebra tiles?
Andrew [12]

Answer:

C

Step-by-step explanation:

Blue is postive and Red is Negative so you would just write them down as seen and because x^2 is negative in the second equation there will be a subtraction sign to represent it.

3 0
3 years ago
A hyperbola centered at the origin has vertices at (± √33,0) and foci at (± √59,0).
oee [108]

Answer:

x^2/33 + y^2/26 = 1

Step-by-step explanation:

The formula for a hyperbola centered at the origin is:

x^2/a^2 - y^2/b^2 = 1

The vertices are located at (±a, 0), so we have that the value of a is √33

The foci are located at (±c, 0), where c^2 = a^2 + b^2

So if we have that c = √59, we can find the value of b:

59 = 33 + b^2

b^2 = 26

b = √26

So the formula for this hyperbole is:

x^2/33 + y^2/26 = 1

6 0
3 years ago
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