By definition you have that the tangent of an angle in a right triangle is given by the quotient between the sine of the angle and the cosine of the angle.
Since we know how much the sine and the cosine measure (we have the sides of the triangles as data), then the tangent is given by:
A. tan Y= y/z
answer
A. tan Y= y/z

5 0

3 years ago

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Perform the indicated operation: (-1 1/2)(-3/2)

LiRa [457]

Answer:

=8 1/4 as a fraction or 8.25 in decimal form.

Step-by-step explanation:

The indicated operation is the product of the two fractions. Multiplication opens the brackets.

(-11/2)×(-3/2)

=(-11×-3)/(2×2)

=33/4

The negative signs before each term cancel out in multiplication and division.

=33/4 =8 1/4= 8.25

Choose 1 answer among the improper fraction, Mixed fraction or the decimal.

6 0

3 years ago

If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)

sertanlavr [38]

Answer:

Final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

Step-by-step explanation:

given functions are $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

Now we need to find about what is the value of $g\left(x\right)*f\left(x\right)$ .

$g\left(x\right)*f\left(x\right)$ simply means we need to multiply the value of $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

$g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)$

$g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$

Hence final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

5 0

3 years ago

A number is between 16 and 21. It has prime factors of 2, and 3. What is the number?

Advocard [28]

Answer:18

Step-by-step explanation: 18=2.3.3

6 0

3 years ago