Answer:



Step-by-step explanation:
Given
Let
A = Event of being a universal donor.
So:


Solving (a): Mean and Standard deviation.
The mean is:



The standard deviation is:




Solving (b): P(x = 3)
The event is a binomial event an dthe probability is calculated as:

So, we have:




Answer:
When we have a number like:
1.0x10^n
To rewrite this in standard form, we need to:
if n is positive, we move the decimal point n times to the right, adding zeros when necessary.
1.0x10^3
n = 3. then we add 3 zeros between the one and the decimal point, this is:
1.0x10^3 = 1000
if n< 0, then we move the decimal point n times to the left.
If we had:
1.0x10^-3
We move the decimal point 3 times to the left, adding zeros as this is needed.
1.0x10^-3 = 0.001
if n = 0, we have:
1.0x10^0 = 1.0
Now let's rewrite all the given numbers:
A) 3.4x10^-1 = 0.34
B) 1.36x10^6 = 1360000
C) 7.9x10^0 = 7.9
D) 2.4x10^5 = 240000
E) 5.21x10^-3 = 0.00521
F) 4.3x10^-2 = 0.043
Answer:
D
Step-by-step explanation:
They didn't provide the number for one of the faces btw..
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Factoring is decomposing a higher powered expression into a lower powered expressions that are multiplied together. Since (a-b)(a^2+ab+b^2) is lower powered than a^3-b^3, (a-b)(a^2+ab+b^2) is more simplified.
The Difference of Cubes formula shows up frequently in mathematics courses and should be memorized.
The formula for factoring the difference of cubes is (a^3 - b^3)= (a-b)(a^2+ab+b^2). It works because if (a-b)(a^2+ab+b^2) is multiplied it out, then it becomes a^3 - b^3. This was probably originally determined by trial and error a long time ago.
Since x is cubed and 8 is 2^3 it factors with the Difference of Cubes Formula. (x^3-2^3)=(x-2)(x^2+2x+2^2)=(x^2+2x+4)