If your into country the song
Don’t by Billy Currington
is a good song <3
Proportional Relationships
If the variables x and y are in a proportional relationship, then:
y = kx
Where k is the constant of proportionality that can be found as follows:

If we are given a pair of values (x, y), we can find the value of k and use it to fill the rest of the table.
For example, Table 1 relates the cost y of x pounds of some items. We are given the pair (2, 2.50). We can calculate the value of k:

Now, for each value of x, multiply by this factor and get the value of y. For example, for x = 3:
y = 1.25 * 3 = 3.75
This value is also given and verifies the correct proportion obtained above.
For x = 4:
y = 1.25 * 4 = 5
For x = 7:
y = 1.25 * 7 = 8.75
For x = 10:
y = 1.25 * 10 = 12.50
Now for table 2, we are given the pair (3, 4.5) which gives us the value of k:

Apply this constant for the rest of the table.
For x = 4:
y = 1.5 * 4 = 6
For x = 5:
y = 1.5 * 5 = 7.50
For x = 8:
y = 1.5 * 8 = 12
The last column doesn't give us the value of x but the value of y, so we need to solve for x:

For y = 15:
Answer:
Step-by-step explanation:
------(I)
![LHS =\dfrac{Cos \ A}{1+Sin \ A}+\dfrac{1+Sin \ A}{Cos \ A}\\\\\\ = \dfrac{1-Sin \A}{Cos \ A}+\dfrac{1+Sin \ A}{Cos \ A} \ [from \ equation \ (I)]\\\\\\=\dfrac{1-Sin \ A + 1 - Sin \ A}{Cos \ A}\\\\=\dfrac{2}{Cos \ A}\\\\\\=2*Sec \ A = RHS](https://tex.z-dn.net/?f=LHS%20%3D%5Cdfrac%7BCos%20%5C%20A%7D%7B1%2BSin%20%5C%20A%7D%2B%5Cdfrac%7B1%2BSin%20%5C%20A%7D%7BCos%20%5C%20A%7D%5C%5C%5C%5C%5C%5C%20%3D%20%5Cdfrac%7B1-Sin%20%5CA%7D%7BCos%20%5C%20A%7D%2B%5Cdfrac%7B1%2BSin%20%5C%20A%7D%7BCos%20%5C%20A%7D%20%5C%20%5Bfrom%20%5C%20equation%20%5C%20%28I%29%5D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B1-Sin%20%5C%20A%20%2B%201%20-%20Sin%20%5C%20A%7D%7BCos%20%5C%20A%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2%7D%7BCos%20%5C%20A%7D%5C%5C%5C%5C%5C%5C%3D2%2ASec%20%5C%20A%20%3D%20RHS)
Answer:
y-9= -3(x+2)
Step-by-step explanation:
y-y1= "M" (x-x1)
y1= 9
X1= -2