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2 years ago

Harvey can run 3 1/6 km in 1/4 hour. Harvey runs at a constant rate

Mathematics

1 answer:

lyudmila [28]2 years ago

6 0

Answer:

12 2/3 km/hour or 12.666 km/hour

Step-by-step explanation:

Because 3 1/6 is the rate for every quarter hour, simply multiply that rate by 4 in order to get the average speed over the course of an hour.

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Sam divided A rectangle into 8 congruent rectangles that each have the area shown. what is tge area of tge rectangle befoe sam d

aniked [119]

No area is shown. So befoe sam divided it,
the area of tge original rectangle was . . .

8 x 0 = zero .

3 0

3 years ago

Find the product -1.2(0.04)

patriot [66]

Answer:

-0.048

Step-by-step explanation:

-1.2 * 0.04 = -1.2 * 4 / 100 = -4.8 / 100 = -).048

4 0

2 years ago

A company earns a profit of $100 the first month it is in business. Every month after that, the company earns a profit that is 1

Jobisdone [24]

Answer is $506.25.
first month is $100,
second month is 100 times 1.5 which is 150.
thirst month is 150 times 1.5 which is 225.
fourth month is 225 times 1.5 which is 337.5
fifth month is 337.5 times 1.5 which is 506.25

3 0

3 years ago

Easy 100 points, plz answer ASP! Please include an explanation!!

valina [46]

Answer:

The third option

Step-by-step explanation:

the most reasonable

6 0

3 years ago

Read 2 more answers

If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

8 0

1 year ago