I cant see it please send another pic of it. closer to the screen.
Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
</span>
Answer:
- attached graph
- Horizontal Asymptote: y = 5
- twon whole number points are (4,4) and (5,1)
Step-by-step explanation:
- Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote
y = -4^(x-4) + 5
= -4^(4-4) + 5
= -4^(0) + 5
= -1 + 5
= 4
y = -4^(x-4) + 5
= -4^(5-4) + 5
= -4^(1) + 5
= -4 + 5
= 1
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
Answer:
no mistakes
Step-by-step explanation:
4 * 3^x = 324
Divide each side by 4
4/4 * 3^x = 324/4
3^x = 81
Rewriting 81 as a power of 3
3^x = 3^4
Since the bases are the same, the powers are the same
x=4
