How to evaluate the expression 6x-14

To pass science, a student must earn at least a grade of 70. How many students failed this science class?

Colt1911 [192]

Answer:

7 students.

Step-by-step explanation:

To pass science, a student requires at least 70 grades so students who scored below 70 will be failed.

From the given bar chart we can calculate the number of students who scored below 70 grades

Students who earned 50 - 59 = 2

Students who earned 60 - 69 = 5

Therefore, number of students who failed were

2 + 5 = 7 students.

4 0

3 years ago

Read 2 more answers

You are planning on making 250 liters of chili for a big fundraiser you are throwing. You want the

Anvisha [2.4K]

Answer:

30%

Step-by-step explanation:

because you use %

so that is why i think but i am not sure

7 0

3 years ago

OLLEGE

Sophie [7]

Part 1

$(f\circ g)(x)=f(\sqrt{x})=4\sqrt{x}+1$

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is $\boxed{[0, \infty)}$

Part 2

$(g \circ f)(x)=g(4x+1)=\sqrt{4x+1}$

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

$4x+1 \geq 0\\\\4x \geq -1\\\\x \geq -\frac{1}{4}$

Thus, the domain in interval notation is $\boxed{\left[-\frac{1}{4}, \infty)}$

8 0

2 years ago

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0

1 year ago

The value of a gold coin picturing the head of the Roman Emperor Vespasian is increasing at the rate of 5% per year. If the coin

bazaltina [42]

Answer:

255.75

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers