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klemol [59]
3 years ago
7

A professional baseball team won 84 games.The team won 14 more games than it lost.There were no ties.How many games did the team

lose?How many did it play?
Mathematics
1 answer:
babunello [35]3 years ago
7 0
Hello There!

Games won = 84
Games lost = 84 - 14
Games lost = 70
Total games played = games lost + games lost
Total games played = 84 + 70
Total games played = 154.

They played 154 games and lost 70 games.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
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Connie sells lemonade for $0.25 per small cup and $0.75 per large cup.
FrozenT [24]

Answer:

Connie must sell 4 large cups.

c = 0.25 per/cup

C = 0.75 per/cup

c × 20 = $5

C × 5 = 3.75 ≈ 4

C × 4 = $3

Product of "c" + Product of "C" = $8.00

5 0
3 years ago
Read 2 more answers
Let the function be f defined by f (x) = 12 - 5x
marissa [1.9K]

(a) No

f(x) = 12 - 5x

f(0) = 12 - 5(0)

f(x) = 12 - 0

f(x) = 12

Hence,

f(0) is unequal to 0.

(b)

f(x) = 12 - 5x

f( - 1) = 12 - 5( - 1)

f( - 1) = 12 + 5

f( - 1) = 17

(c)

f(x) = 12 - 5x

f(x) = 6

6 = 12 - 5x

6 - 12 =  - 5x

- 6 =  - 5x

6 = 5x

\frac{6}{5}  = x

7 0
3 years ago
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Leokris [45]

Answer:

Step-by-step explanation:

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3 0
3 years ago
Which is true about the polynomial 9x²y – 6x - 5y^2
Ostrovityanka [42]

Answer:

D

Step-by-step explanation:

It is a trinomial with a degree of 3.

This is the correct answer on the exam.

7 0
3 years ago
Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What
777dan777 [17]

Answer:

B) \frac{3}{4} x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

                               = 40 units

Dilating KMPT by a scale factor of \frac{3}{4} would create K'M'P'T' of dimensions; \frac{3}{4} × 12 units by \frac{3}{4} × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

                                  = 2(9 + 6)

                                  = 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be  \frac{3}{4} × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

         perimeter of K'M'P'T' = \frac{3}{4} * x units

                                            = \frac{3}{4}x units

6 0
4 years ago
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